2x+((20-x)-3)=30

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Solution for 2x+((20-x)-3)=30 equation: 



2x+((20-x)-3)=30

We move all terms to the left:

2x+((20-x)-3)-(30)=0

We add all the numbers together, and all the variables

2x+((-1x+20)-3)-30=0



We calculate terms in parentheses: +((-1x+20)-3), so:

(-1x+20)-3

We get rid of parentheses

-1x+20-3

We add all the numbers together, and all the variables

-1x+17

Back to the equation:

+(-1x+17)



We get rid of parentheses

2x-1x+17-30=0

We add all the numbers together, and all the variables

x-13=0

We move all terms containing x to the left, all other terms to the right

x=13

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