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1/2(2x+12)=1/4-3x
We move all terms to the left:
1/2(2x+12)-(1/4-3x)=0
Domain of the equation: 2(2x+12)!=0
x∈R
Domain of the equation: 4-3x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-3x)!=-4
x!=-4/1
x!=-4
x∈R
1/2(2x+12)-(-3x+1/4)=0
We get rid of parentheses
1/2(2x+12)+3x-1/4=0
We calculate fractions
There is no solution for this equation
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