3(-x)+8x-4=x+12

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Solution for 3(-x)+8x-4=x+12 equation: 



3(-x)+8x-4=x+12

We move all terms to the left:

3(-x)+8x-4-(x+12)=0

We add all the numbers together, and all the variables

3(-1x)+8x-(x+12)-4=0

We add all the numbers together, and all the variables

8x+3(-1x)-(x+12)-4=0

We multiply parentheses

8x-3x-(x+12)-4=0

We get rid of parentheses

8x-3x-x-12-4=0

We add all the numbers together, and all the variables

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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