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13x+3-5x=3(1+2x)+2x
We move all terms to the left:
13x+3-5x-(3(1+2x)+2x)=0
We add all the numbers together, and all the variables
13x-5x-(3(2x+1)+2x)+3=0
We add all the numbers together, and all the variables
8x-(3(2x+1)+2x)+3=0
We calculate terms in parentheses: -(3(2x+1)+2x), so:We get rid of parentheses
3(2x+1)+2x
We add all the numbers together, and all the variables
2x+3(2x+1)
We multiply parentheses
2x+6x+3
We add all the numbers together, and all the variables
8x+3
Back to the equation:
-(8x+3)
8x-8x-3+3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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