-2(3z+2)=-4(1-2z)

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Solution for -2(3z+2)=-4(1-2z) equation: 



-2(3z+2)=-4(1-2z)

We move all terms to the left:

-2(3z+2)-(-4(1-2z))=0

We add all the numbers together, and all the variables

-2(3z+2)-(-4(-2z+1))=0

We multiply parentheses

-6z-(-4(-2z+1))-4=0



We calculate terms in parentheses: -(-4(-2z+1)), so:

-4(-2z+1)

We multiply parentheses

8z-4

Back to the equation:

-(8z-4)



We get rid of parentheses

-6z-8z+4-4=0

We add all the numbers together, and all the variables

-14z=0

z=0/-14

z=0

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