2/3(x-1)=3/2(x+1)

Solution for 2/3(x-1)=3/2(x+1) equation:

2/3(x-1)=3/2(x+1)

We move all terms to the left:

2/3(x-1)-(3/2(x+1))=0


Domain of the equation: 3(x-1)!=0

x∈R



Domain of the equation: 2(x+1))!=0

x∈R


We calculate fractions


(4xx/(3(x-1)*2(x+1)))+(-9xx/(3(x-1)*2(x+1)))=0


We calculate terms in parentheses: +(4xx/(3(x-1)*2(x+1))), so:

4xx/(3(x-1)*2(x+1))

We multiply all the terms by the denominator


4xx

Back to the equation:

+(4xx)



We calculate terms in parentheses: +(-9xx/(3(x-1)*2(x+1))), so:

-9xx/(3(x-1)*2(x+1))

We multiply all the terms by the denominator


-9xx

Back to the equation:

+(-9xx)


We get rid of parentheses

4xx-9xx=0