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(2(x+5))/(5-x)=6
We move all terms to the left:
(2(x+5))/(5-x)-(6)=0
Domain of the equation: (5-x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-x!=-5
x!=-5/-1
x!=+5
x∈R
(2(x+5))/(-1x+5)-6=0
We multiply all the terms by the denominator
(2(x+5))-6*(-1x+5)=0
We calculate terms in parentheses: +(2(x+5)), so:We multiply parentheses
2(x+5)
We multiply parentheses
2x+10
Back to the equation:
+(2x+10)
(2x+10)+6x-30=0
We get rid of parentheses
2x+6x+10-30=0
We add all the numbers together, and all the variables
8x-20=0
We move all terms containing x to the left, all other terms to the right
8x=20
x=20/8
x=2+1/2
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