7(t-6)+5=6(2t+2)-8

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Solution for 7(t-6)+5=6(2t+2)-8 equation: 



7(t-6)+5=6(2t+2)-8

We move all terms to the left:

7(t-6)+5-(6(2t+2)-8)=0

We multiply parentheses

7t-(6(2t+2)-8)-42+5=0



We calculate terms in parentheses: -(6(2t+2)-8), so:

6(2t+2)-8

We multiply parentheses

12t+12-8

We add all the numbers together, and all the variables

12t+4

Back to the equation:

-(12t+4)



We add all the numbers together, and all the variables

7t-(12t+4)-37=0

We get rid of parentheses

7t-12t-4-37=0

We add all the numbers together, and all the variables

-5t-41=0

We move all terms containing t to the left, all other terms to the right

-5t=41

t=41/-5

t=-8+1/5

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