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(12-x)/3=9x-2
We move all terms to the left:
(12-x)/3-(9x-2)=0
We add all the numbers together, and all the variables
(-1x+12)/3-(9x-2)=0
We get rid of parentheses
(-1x+12)/3-9x+2=0
We multiply all the terms by the denominator
(-1x+12)-9x*3+2*3=0
We add all the numbers together, and all the variables
(-1x+12)-9x*3+6=0
Wy multiply elements
(-1x+12)-27x+6=0
We get rid of parentheses
-1x-27x+12+6=0
We add all the numbers together, and all the variables
-28x+18=0
We move all terms containing x to the left, all other terms to the right
-28x=-18
x=-18/-28
x=9/14
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