2/(x+2)=3/(x+4)

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Solution for 2/(x+2)=3/(x+4) equation: 



2/(x+2)=3/(x+4)

We move all terms to the left:

2/(x+2)-(3/(x+4))=0



Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R





Domain of the equation: (x+4))!=0

x∈R



We calculate fractions


2x/((x+2)*(x+4)))+(-(3*(x+2))/((x+2)*(x+4)))=0



We calculate terms in parentheses: -(3*(x+2))/((x+2)*(x+4))), so:

3*(x+2))/((x+2)*(x+4))

We multiply all the terms by the denominator


3*(x+2))

We multiply parentheses

3x+

We add all the numbers together, and all the variables

3x

Back to the equation:

-(3x)



We add all the numbers together, and all the variables

-3x+2x/((x+2)*(x+4)))+(=0

We multiply all the terms by the denominator


-3x*((x+2)*(x+4)))+(+2x=0

We add all the numbers together, and all the variables

2x-3x*((x+2)*(x+4)))+(=0

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