2(b+30)=33+5b

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Solution for 2(b+30)=33+5b equation: 



2(b+30)=33+5b

We move all terms to the left:

2(b+30)-(33+5b)=0

We add all the numbers together, and all the variables

2(b+30)-(5b+33)=0

We multiply parentheses

2b-(5b+33)+60=0

We get rid of parentheses

2b-5b-33+60=0

We add all the numbers together, and all the variables

-3b+27=0

We move all terms containing b to the left, all other terms to the right

-3b=-27

b=-27/-3

b=+9

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