4(2v+2)+3v+7=4(v+5)+2v

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Solution for 4(2v+2)+3v+7=4(v+5)+2v equation: 



4(2v+2)+3v+7=4(v+5)+2v

We move all terms to the left:

4(2v+2)+3v+7-(4(v+5)+2v)=0

We add all the numbers together, and all the variables

3v+4(2v+2)-(4(v+5)+2v)+7=0

We multiply parentheses

3v+8v-(4(v+5)+2v)+8+7=0



We calculate terms in parentheses: -(4(v+5)+2v), so:

4(v+5)+2v

We add all the numbers together, and all the variables

2v+4(v+5)

We multiply parentheses

2v+4v+20

We add all the numbers together, and all the variables

6v+20

Back to the equation:

-(6v+20)



We add all the numbers together, and all the variables

11v-(6v+20)+15=0

We get rid of parentheses

11v-6v-20+15=0

We add all the numbers together, and all the variables

5v-5=0

We move all terms containing v to the left, all other terms to the right

5v=5

v=5/5

v=1

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