5y-5=4(2y-2)

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Solution for 5y-5=4(2y-2) equation: 



5y-5=4(2y-2)

We move all terms to the left:

5y-5-(4(2y-2))=0



We calculate terms in parentheses: -(4(2y-2)), so:

4(2y-2)

We multiply parentheses

8y-8

Back to the equation:

-(8y-8)



We get rid of parentheses

5y-8y+8-5=0

We add all the numbers together, and all the variables

-3y+3=0

We move all terms containing y to the left, all other terms to the right

-3y=-3

y=-3/-3

y=1

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