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(2x-5)(x-1)=-6
We move all terms to the left:
(2x-5)(x-1)-(-6)=0
We add all the numbers together, and all the variables
(2x-5)(x-1)+6=0
We multiply parentheses ..
(+2x^2-2x-5x+5)+6=0
We get rid of parentheses
2x^2-2x-5x+5+6=0
We add all the numbers together, and all the variables
2x^2-7x+11=0
a = 2; b = -7; c = +11;
Δ = b2-4ac
Δ = -72-4·2·11
Δ = -39
Delta is less than zero, so there is no solution for the equation
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