2(b+3)-(b-4)=15

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Solution for 2(b+3)-(b-4)=15 equation: 



2(b+3)-(b-4)=15

We move all terms to the left:

2(b+3)-(b-4)-(15)=0

We multiply parentheses

2b-(b-4)+6-15=0

We get rid of parentheses

2b-b+4+6-15=0

We add all the numbers together, and all the variables

b-5=0

We move all terms containing b to the left, all other terms to the right

b=5

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