10a=(3a-4)+15

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Solution for 10a=(3a-4)+15 equation:



10a=(3a-4)+15
We move all terms to the left:
10a-((3a-4)+15)=0
We calculate terms in parentheses: -((3a-4)+15), so:
(3a-4)+15
We get rid of parentheses
3a-4+15
We add all the numbers together, and all the variables
3a+11
Back to the equation:
-(3a+11)
We get rid of parentheses
10a-3a-11=0
We add all the numbers together, and all the variables
7a-11=0
We move all terms containing a to the left, all other terms to the right
7a=11
a=11/7
a=1+4/7

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