3*x*x=2*x*(x+50)

Solution for 3*x*x=2*x*(x+50) equation:

3x*x=2x(x+50)

We move all terms to the left:

3x*x-(2x(x+50))=0

Wy multiply elements

3x^2-(2x(x+50))=0


We calculate terms in parentheses: -(2x(x+50)), so:

2x(x+50)

We multiply parentheses

2x^2+100x

Back to the equation:

-(2x^2+100x)


We get rid of parentheses

3x^2-2x^2-100x=0

We add all the numbers together, and all the variables

x^2-100x=0

a = 1; b = -100; c = 0;
Δ = b2-4ac
Δ = -1002-4·1·0
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-100}{2*1}=\frac{0}{2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+100}{2*1}=\frac{200}{2}
=100
$