3x2-280x+-3300=0

Solution for 3x2-280x+-3300=0 equation:

3x^2-280x+-3300=0

We add all the numbers together, and all the variables

3x^2-280x=0

a = 3; b = -280; c = 0;
Δ = b2-4ac
Δ = -2802-4·3·0
Δ = 78400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{78400}=280$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-280)-280}{2*3}=\frac{0}{6}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-280)+280}{2*3}=\frac{560}{6}
=93+1/3
$