2(3x-3)+6(2x-4)=42

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Solution for 2(3x-3)+6(2x-4)=42 equation: 



2(3x-3)+6(2x-4)=42

We move all terms to the left:

2(3x-3)+6(2x-4)-(42)=0

We multiply parentheses

6x+12x-6-24-42=0

We add all the numbers together, and all the variables

18x-72=0

We move all terms containing x to the left, all other terms to the right

18x=72

x=72/18

x=4

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