82=z-48

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Solution for 82=z-48 equation: 



82=z-48

We move all terms to the left:

82-(z-48)=0

We get rid of parentheses

-z+48+82=0

We add all the numbers together, and all the variables

-1z+130=0

We move all terms containing z to the left, all other terms to the right

-z=-130

z=-130/-1

z=+130

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