3(x+2)+3(2x+1)=99

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Solution for 3(x+2)+3(2x+1)=99 equation: 



3(x+2)+3(2x+1)=99

We move all terms to the left:

3(x+2)+3(2x+1)-(99)=0

We multiply parentheses

3x+6x+6+3-99=0

We add all the numbers together, and all the variables

9x-90=0

We move all terms containing x to the left, all other terms to the right

9x=90

x=90/9

x=10

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