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2(3x+4)-2(2x-5)=2(4x+2)-2(x+1)
We move all terms to the left:
2(3x+4)-2(2x-5)-(2(4x+2)-2(x+1))=0
We multiply parentheses
6x-4x-(2(4x+2)-2(x+1))+8+10=0
We calculate terms in parentheses: -(2(4x+2)-2(x+1)), so:We add all the numbers together, and all the variables
2(4x+2)-2(x+1)
We multiply parentheses
8x-2x+4-2
We add all the numbers together, and all the variables
6x+2
Back to the equation:
-(6x+2)
2x-(6x+2)+18=0
We get rid of parentheses
2x-6x-2+18=0
We add all the numbers together, and all the variables
-4x+16=0
We move all terms containing x to the left, all other terms to the right
-4x=-16
x=-16/-4
x=+4
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