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15=5/3(x+12)
We move all terms to the left:
15-(5/3(x+12))=0
Domain of the equation: 3(x+12))!=0We multiply all the terms by the denominator
x∈R
-(5+15*3(x+12))=0
We calculate terms in parentheses: -(5+15*3(x+12)), so:
5+15*3(x+12)
determiningTheFunctionDomain 15*3(x+12)+5
Wy multiply elements
45x(x+5
Back to the equation:
-(45x(x+5)
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