40+10(4y-8)-16(3y-5)=0

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Solution for 40+10(4y-8)-16(3y-5)=0 equation: 



40+10(4y-8)-16(3y-5)=0

We multiply parentheses

40y-48y-80+80+40=0

We add all the numbers together, and all the variables

-8y+40=0

We move all terms containing y to the left, all other terms to the right

-8y=-40

y=-40/-8

y=+5

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