2(x+2)=3+(x-1)

Solution for 2(x+2)=3+(x-1) equation:

2(x+2)=3+(x-1)

We move all terms to the left:

2(x+2)-(3+(x-1))=0

We multiply parentheses

2x-(3+(x-1))+4=0


We calculate terms in parentheses: -(3+(x-1)), so:

3+(x-1)

determiningTheFunctionDomain
(x-1)+3

We get rid of parentheses

x-1+3

We add all the numbers together, and all the variables

x+2

Back to the equation:

-(x+2)


We get rid of parentheses

2x-x-2+4=0

We add all the numbers together, and all the variables

x+2=0

We move all terms containing x to the left, all other terms to the right

x=-2