20(x+1)=12(3x-2)

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Solution for 20(x+1)=12(3x-2) equation: 



20(x+1)=12(3x-2)

We move all terms to the left:

20(x+1)-(12(3x-2))=0

We multiply parentheses

20x-(12(3x-2))+20=0



We calculate terms in parentheses: -(12(3x-2)), so:

12(3x-2)

We multiply parentheses

36x-24

Back to the equation:

-(36x-24)



We get rid of parentheses

20x-36x+24+20=0

We add all the numbers together, and all the variables

-16x+44=0

We move all terms containing x to the left, all other terms to the right

-16x=-44

x=-44/-16

x=2+3/4

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