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(9x+12)3x=180
We move all terms to the left:
(9x+12)3x-(180)=0
We multiply parentheses
27x^2+36x-180=0
a = 27; b = 36; c = -180;
Δ = b2-4ac
Δ = 362-4·27·(-180)
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{20736}=144$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-144}{2*27}=\frac{-180}{54} =-3+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+144}{2*27}=\frac{108}{54} =2 $
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