6(3x+3)=7(x+16)

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Solution for 6(3x+3)=7(x+16) equation: 



6(3x+3)=7(x+16)

We move all terms to the left:

6(3x+3)-(7(x+16))=0

We multiply parentheses

18x-(7(x+16))+18=0



We calculate terms in parentheses: -(7(x+16)), so:

7(x+16)

We multiply parentheses

7x+112

Back to the equation:

-(7x+112)



We get rid of parentheses

18x-7x-112+18=0

We add all the numbers together, and all the variables

11x-94=0

We move all terms containing x to the left, all other terms to the right

11x=94

x=94/11

x=8+6/11

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