-38=4(v-5)-2v

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Solution for -38=4(v-5)-2v equation: 



-38=4(v-5)-2v

We move all terms to the left:

-38-(4(v-5)-2v)=0



We calculate terms in parentheses: -(4(v-5)-2v), so:

4(v-5)-2v

We add all the numbers together, and all the variables

-2v+4(v-5)

We multiply parentheses

-2v+4v-20

We add all the numbers together, and all the variables

2v-20

Back to the equation:

-(2v-20)



We get rid of parentheses

-2v+20-38=0

We add all the numbers together, and all the variables

-2v-18=0

We move all terms containing v to the left, all other terms to the right

-2v=18

v=18/-2

v=-9

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