129-6(x)=3(x)+21

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Solution for 129-6(x)=3(x)+21 equation: 



129-6(x)=3(x)+21

We move all terms to the left:

129-6(x)-(3(x)+21)=0

We get rid of parentheses

-6x-3x-21+129=0

We add all the numbers together, and all the variables

-9x+108=0

We move all terms containing x to the left, all other terms to the right

-9x=-108

x=-108/-9

x=+12

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