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3k+4=3(k+3/4)
We move all terms to the left:
3k+4-(3(k+3/4))=0
We add all the numbers together, and all the variables
3k-(3(+k+3/4))+4=0
We multiply all the terms by the denominator
3k*4))-(3(+k+3+4*4))=0
We add all the numbers together, and all the variables
3k*4))-(3(k+19))=0
We add all the numbers together, and all the variables
3k*4))-(3(k=0
Wy multiply elements
12k^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$k=\frac{-b}{2a}=\frac{0}{24}=0$
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