4(5-y)=2(3y-10)

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Solution for 4(5-y)=2(3y-10) equation: 



4(5-y)=2(3y-10)

We move all terms to the left:

4(5-y)-(2(3y-10))=0

We add all the numbers together, and all the variables

4(-1y+5)-(2(3y-10))=0

We multiply parentheses

-4y-(2(3y-10))+20=0



We calculate terms in parentheses: -(2(3y-10)), so:

2(3y-10)

We multiply parentheses

6y-20

Back to the equation:

-(6y-20)



We get rid of parentheses

-4y-6y+20+20=0

We add all the numbers together, and all the variables

-10y+40=0

We move all terms containing y to the left, all other terms to the right

-10y=-40

y=-40/-10

y=+4

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