3(3x-1)-5(4x-2)+9(2-2x)=15

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Solution for 3(3x-1)-5(4x-2)+9(2-2x)=15 equation: 



3(3x-1)-5(4x-2)+9(2-2x)=15

We move all terms to the left:

3(3x-1)-5(4x-2)+9(2-2x)-(15)=0

We add all the numbers together, and all the variables

3(3x-1)-5(4x-2)+9(-2x+2)-15=0

We multiply parentheses

9x-20x-18x-3+10+18-15=0

We add all the numbers together, and all the variables

-29x+10=0

We move all terms containing x to the left, all other terms to the right

-29x=-10

x=-10/-29

x=10/29

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