5(k+2)-7=13-(4-k)69

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Solution for 5(k+2)-7=13-(4-k)69 equation: 



5(k+2)-7=13-(4-k)69

We move all terms to the left:

5(k+2)-7-(13-(4-k)69)=0

We add all the numbers together, and all the variables

5(k+2)-(13-(-1k+4)69)-7=0

We multiply parentheses

5k-(13-(-1k+4)69)+10-7=0



We calculate terms in parentheses: -(13-(-1k+4)69), so:

13-(-1k+4)69

determiningTheFunctionDomain
-(-1k+4)69+13

We multiply parentheses

69k-276+13

We add all the numbers together, and all the variables

69k-263

Back to the equation:

-(69k-263)



We add all the numbers together, and all the variables

5k-(69k-263)+3=0

We get rid of parentheses

5k-69k+263+3=0

We add all the numbers together, and all the variables

-64k+266=0

We move all terms containing k to the left, all other terms to the right

-64k=-266

k=-266/-64

k=4+5/32

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