11.2x(3x+3)=3(2x+2)

Solution for 11.2x(3x+3)=3(2x+2) equation:

11.2x(3x+3)=3(2x+2)

We move all terms to the left:

11.2x(3x+3)-(3(2x+2))=0

We multiply parentheses

33x^2+33x-(3(2x+2))=0


We calculate terms in parentheses: -(3(2x+2)), so:

3(2x+2)

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)


We get rid of parentheses

33x^2+33x-6x-6=0

We add all the numbers together, and all the variables

33x^2+27x-6=0

a = 33; b = 27; c = -6;
Δ = b2-4ac
Δ = 272-4·33·(-6)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-39}{2*33}=\frac{-66}{66}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+39}{2*33}=\frac{12}{66}
=2/11
$