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5/x+3/2x=13
We move all terms to the left:
5/x+3/2x-(13)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x!=0We calculate fractions
x!=0/2
x!=0
x∈R
10x/2x^2+3x/2x^2-13=0
We multiply all the terms by the denominator
10x+3x-13*2x^2=0
We add all the numbers together, and all the variables
13x-13*2x^2=0
Wy multiply elements
-26x^2+13x=0
a = -26; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·(-26)·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*-26}=\frac{-26}{-52} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*-26}=\frac{0}{-52} =0 $
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