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X-(3X+5)=12-(X+2)
We move all terms to the left:
X-(3X+5)-(12-(X+2))=0
We get rid of parentheses
X-3X-(12-(X+2))-5=0
We calculate terms in parentheses: -(12-(X+2)), so:We add all the numbers together, and all the variables
12-(X+2)
determiningTheFunctionDomain -(X+2)+12
We get rid of parentheses
-X-2+12
We add all the numbers together, and all the variables
-1X+10
Back to the equation:
-(-1X+10)
-2X-(-1X+10)-5=0
We get rid of parentheses
-2X+1X-10-5=0
We add all the numbers together, and all the variables
-1X-15=0
We move all terms containing X to the left, all other terms to the right
-X=15
X=15/-1
X=-15
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