2(3x+4)+4=6-2(x+3)

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Solution for 2(3x+4)+4=6-2(x+3) equation: 



2(3x+4)+4=6-2(x+3)

We move all terms to the left:

2(3x+4)+4-(6-2(x+3))=0

We multiply parentheses

6x-(6-2(x+3))+8+4=0



We calculate terms in parentheses: -(6-2(x+3)), so:

6-2(x+3)

determiningTheFunctionDomain
-2(x+3)+6

We multiply parentheses

-2x-6+6

We add all the numbers together, and all the variables

-2x

Back to the equation:

-(-2x)



We add all the numbers together, and all the variables

6x-(-2x)+12=0

We get rid of parentheses

6x+2x+12=0

We add all the numbers together, and all the variables

8x+12=0

We move all terms containing x to the left, all other terms to the right

8x=-12

x=-12/8

x=-1+1/2

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