11(x-3)+4(2x+1)=5(3x-)+13

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Solution for 11(x-3)+4(2x+1)=5(3x-)+13 equation: 



11(x-3)+4(2x+1)=5(3x-)+13

We move all terms to the left:

11(x-3)+4(2x+1)-(5(3x-)+13)=0

We add all the numbers together, and all the variables

11(x-3)+4(2x+1)-(5(+3x)+13)=0

We multiply parentheses

11x+8x-(5(+3x)+13)-33+4=0



We calculate terms in parentheses: -(5(+3x)+13), so:

5(+3x)+13

We multiply parentheses

15x+13

Back to the equation:

-(15x+13)



We add all the numbers together, and all the variables

19x-(15x+13)-29=0

We get rid of parentheses

19x-15x-13-29=0

We add all the numbers together, and all the variables

4x-42=0

We move all terms containing x to the left, all other terms to the right

4x=42

x=42/4

x=10+1/2

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