13-(5-4m)=-7+(2-m)

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Solution for 13-(5-4m)=-7+(2-m) equation: 



13-(5-4m)=-7+(2-m)

We move all terms to the left:

13-(5-4m)-(-7+(2-m))=0

We add all the numbers together, and all the variables

-(-4m+5)-(-7+(-1m+2))+13=0

We get rid of parentheses

4m-(-7+(-1m+2))-5+13=0



We calculate terms in parentheses: -(-7+(-1m+2)), so:

-7+(-1m+2)

determiningTheFunctionDomain
(-1m+2)-7

We get rid of parentheses

-1m+2-7

We add all the numbers together, and all the variables

-1m-5

Back to the equation:

-(-1m-5)



We add all the numbers together, and all the variables

4m-(-1m-5)+8=0

We get rid of parentheses

4m+1m+5+8=0

We add all the numbers together, and all the variables

5m+13=0

We move all terms containing m to the left, all other terms to the right

5m=-13

m=-13/5

m=-2+3/5

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