2(y+2)+2=29-(y+3)

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Solution for 2(y+2)+2=29-(y+3) equation: 



2(y+2)+2=29-(y+3)

We move all terms to the left:

2(y+2)+2-(29-(y+3))=0

We multiply parentheses

2y-(29-(y+3))+4+2=0



We calculate terms in parentheses: -(29-(y+3)), so:

29-(y+3)

determiningTheFunctionDomain
-(y+3)+29

We get rid of parentheses

-y-3+29

We add all the numbers together, and all the variables

-1y+26

Back to the equation:

-(-1y+26)



We add all the numbers together, and all the variables

2y-(-1y+26)+6=0

We get rid of parentheses

2y+1y-26+6=0

We add all the numbers together, and all the variables

3y-20=0

We move all terms containing y to the left, all other terms to the right

3y=20

y=20/3

y=6+2/3

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