3(2z-5)-3(1-2z)=12

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Solution for 3(2z-5)-3(1-2z)=12 equation: 



3(2z-5)-3(1-2z)=12

We move all terms to the left:

3(2z-5)-3(1-2z)-(12)=0

We add all the numbers together, and all the variables

3(2z-5)-3(-2z+1)-12=0

We multiply parentheses

6z+6z-15-3-12=0

We add all the numbers together, and all the variables

12z-30=0

We move all terms containing z to the left, all other terms to the right

12z=30

z=30/12

z=2+1/2

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