4(x+1)+3(x+2)=7(x+1)-5

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Solution for 4(x+1)+3(x+2)=7(x+1)-5 equation: 



4(x+1)+3(x+2)=7(x+1)-5

We move all terms to the left:

4(x+1)+3(x+2)-(7(x+1)-5)=0

We multiply parentheses

4x+3x-(7(x+1)-5)+4+6=0



We calculate terms in parentheses: -(7(x+1)-5), so:

7(x+1)-5

We multiply parentheses

7x+7-5

We add all the numbers together, and all the variables

7x+2

Back to the equation:

-(7x+2)



We add all the numbers together, and all the variables

7x-(7x+2)+10=0

We get rid of parentheses

7x-7x-2+10=0

We add all the numbers together, and all the variables

8!=0

There is no solution for this equation

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