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10x+15/5x=2x+1
We move all terms to the left:
10x+15/5x-(2x+1)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
10x+15/5x-2x-1=0
We multiply all the terms by the denominator
10x*5x-2x*5x-1*5x+15=0
Wy multiply elements
50x^2-10x^2-5x+15=0
We add all the numbers together, and all the variables
40x^2-5x+15=0
a = 40; b = -5; c = +15;
Δ = b2-4ac
Δ = -52-4·40·15
Δ = -2375
Delta is less than zero, so there is no solution for the equation
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