42-(2c+4)=(4c+6)+c

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Solution for 42-(2c+4)=(4c+6)+c equation: 



42-(2c+4)=(4c+6)+c

We move all terms to the left:

42-(2c+4)-((4c+6)+c)=0

We get rid of parentheses

-2c-((4c+6)+c)-4+42=0



We calculate terms in parentheses: -((4c+6)+c), so:

(4c+6)+c

We add all the numbers together, and all the variables

c+(4c+6)

We get rid of parentheses

c+4c+6

We add all the numbers together, and all the variables

5c+6

Back to the equation:

-(5c+6)



We add all the numbers together, and all the variables

-2c-(5c+6)+38=0

We get rid of parentheses

-2c-5c-6+38=0

We add all the numbers together, and all the variables

-7c+32=0

We move all terms containing c to the left, all other terms to the right

-7c=-32

c=-32/-7

c=4+4/7

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