6(3x+4)=3(2+x)

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Solution for 6(3x+4)=3(2+x) equation: 



6(3x+4)=3(2+x)

We move all terms to the left:

6(3x+4)-(3(2+x))=0

We add all the numbers together, and all the variables

6(3x+4)-(3(x+2))=0

We multiply parentheses

18x-(3(x+2))+24=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We get rid of parentheses

18x-3x-6+24=0

We add all the numbers together, and all the variables

15x+18=0

We move all terms containing x to the left, all other terms to the right

15x=-18

x=-18/15

x=-1+1/5

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