1/2(x+5)=4(x-3)

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Solution for 1/2(x+5)=4(x-3) equation: 



1/2(x+5)=4(x-3)

We move all terms to the left:

1/2(x+5)-(4(x-3))=0



Domain of the equation: 2(x+5)!=0

x∈R



We multiply all the terms by the denominator


-((4(x-3)))*2(x+5)+1=0



We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





We calculate terms in parentheses: -((4(x-3)))*2(x+5), so:

(4(x-3)))*2(x+5





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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