42-(2c+4)=4)c+6)+c

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Solution for 42-(2c+4)=4)c+6)+c equation: 



42-(2c+4)=4)c+6)+c

We move all terms to the left:

42-(2c+4)-(4)c+6)+c)=0

We add all the numbers together, and all the variables

-4c-(2c+4)+6)+c)+42=0

We get rid of parentheses

-4c-2c+6)+c)+42-4=0

We add all the numbers together, and all the variables

-6c+6)+c)+42-4=0

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