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5(x-3-2x)-3(2-5x)=3(2x+1)
We move all terms to the left:
5(x-3-2x)-3(2-5x)-(3(2x+1))=0
We add all the numbers together, and all the variables
5(-1x-3)-3(-5x+2)-(3(2x+1))=0
We multiply parentheses
-5x+15x-(3(2x+1))-15-6=0
We calculate terms in parentheses: -(3(2x+1)), so:We add all the numbers together, and all the variables
3(2x+1)
We multiply parentheses
6x+3
Back to the equation:
-(6x+3)
10x-(6x+3)-21=0
We get rid of parentheses
10x-6x-3-21=0
We add all the numbers together, and all the variables
4x-24=0
We move all terms containing x to the left, all other terms to the right
4x=24
x=24/4
x=6
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