3(x+2)=-3(x+4)+6

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Solution for 3(x+2)=-3(x+4)+6 equation: 



3(x+2)=-3(x+4)+6

We move all terms to the left:

3(x+2)-(-3(x+4)+6)=0

We multiply parentheses

3x-(-3(x+4)+6)+6=0



We calculate terms in parentheses: -(-3(x+4)+6), so:

-3(x+4)+6

We multiply parentheses

-3x-12+6

We add all the numbers together, and all the variables

-3x-6

Back to the equation:

-(-3x-6)



We get rid of parentheses

3x+3x+6+6=0

We add all the numbers together, and all the variables

6x+12=0

We move all terms containing x to the left, all other terms to the right

6x=-12

x=-12/6

x=-2

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